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Chemistry, 05.12.2021 01:00 DepressionCentral
Given the following reaction, how much 0.115 M KI solution will completely react with the Pb(NO3)2 in 0.118 L of 0.225 M Pb(NO3)2? 2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)
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Chemistry, 22.06.2019 14:30
Consider the reduction reactions and their equilibrium constants. cu+(aq)+e−↽−−⇀cu(s)pb2+(aq)+2e−↽−−⇀pb(s)fe3+(aq)+3e−↽−−⇀fe(=6.2×108=4.0×10−5=9.3×10−3 cu + ( aq ) + e − ↽ − − ⇀ cu ( s ) k =6.2× 10 8 pb 2 + ( aq ) +2 e − ↽ − − ⇀ pb ( s ) k =4.0× 10 − 5 fe 3 + ( aq ) +3 e − ↽ − − ⇀ fe ( s ) k =9.3× 10 − 3 arrange these ions from strongest to weakest oxidizing agent.
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Given the following reaction, how much 0.115 M KI solution will completely react with the Pb(NO3)2 i...
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