Chemistry, 07.12.2021 18:50 Maddifalls1562

Use the following scenario to answer the question. Antonio is experimenting with solutions. He takes a large beaker of distilled water and dissolves salt, and then sugar.

Has Antonio created a solution or a mixture? If it is a solution, identify the solute(s) and solvent(s).

(1 point)

By dissolving salt and sugar in water, Antonio made a solution. Solutions can have many solvents, but only one solute. In this solution, salt and sugar are solvents, and water is the solute.
By dissolving salt and sugar in water, Antonio made a solution. Solutions can have many solvents, but only one solute. In this solution, salt and sugar are solvents, and water is the solute.

By combining three ingredients, Antonio made a mixture. Solutions can only consist of one solvent and one solute.
By combining three ingredients, Antonio made a mixture. Solutions can only consist of one solvent and one solute.

Antonio dissolved salt and sugar in water to form a solution. Solutions can have many solutes, but only one solvent. In this mixture, salt and sugar are solutes, and water is the solvent.
Antonio dissolved salt and sugar in water to form a solution. Solutions can have many solutes, but only one solvent. In this mixture, salt and sugar are solutes, and water is the solvent.

Antonio created a mixture because solutio

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Answer from: Quest

може ли да зареждате повече информация, моля

Answer from: Quest

1.75 is the weight of one medium egg

Answer from: Quest

the missing options are :

(1) lower boiling point and a lower freezing point(2) lower boiling point and a higher freezing point(3) higher boiling point and a lower freezing point(4) higher boiling point and a higher freezing point

answer : the correct answer is option (3) higher boiling point and a lower freezing point

explanation :

when a non volatile solute is added to a solvent like water, it results in elevation of boiling point.

let us find the increase in boiling point of water when cacl₂ is added to water to make a solution of 1 m

step 1 : find molality of the solution

let us assume we have 1 l of solution.

$m = \frac{moles (solute)}{l ( solution)}$

$1 m = \frac{moles (cacl_{2})}{1 l }= 1 mol cacl_{2}$

let us convert this to grams of cacl₂.

molar mass of cacl2 is 111 g/mol

grams of cacl₂ = $1 mol \times \frac{111g}{mol} = 111 g cacl_{2}$

mass of solute = 111 g

assuming density of solution same as water which is 1g/ml we have ,

mass of solution = density * volume

mass of solution = $\frac{1g}{ml} \times 1000 ml = 1000 g$

mass of solution = mass of solvent + mass of solute

mass of solute = 1000g - 111g

mass of solute 889 g = 0.889 kg

the molality of the solution can be calculated as

$molality = \frac{mol (solute)}{kg ( solvent)}$

$molality = \frac{1mol}{0.889kg}$

molality = 1.12 m

step 2 : find boiling point elevation.

the elevation in boiling point is calculated as

$\bigtriangleup t_{b} = i \times k_{b} \times m$

here δtb = boiling point elevation

i = vant hoff factor which is the number of ions formed by the solute .

cacl₂ dissociates as $cacl_{2} \rightarrow ca^{2+} + 2 cl^{-}$

it forms 3 ions . therefore,

i = 3

m = molality which is 1.12 m

kb is constant for a given solvent. for water it is 0.512

$\bigtriangleup t_{b} = 3 \times 0.512 \times 1.12$

$\bigtriangleup t_{b} = 1.7$

the boiling point of water increases by 1.7 °c

step 3: find freezing point depression.

when a non volatile solute is added to water, it results in decrease in freezing point.

the formula to find freezing point depression is

$\bigtriangleup t_{f} = i \times k_{f} \times m$

kf is constant for water and its value is 1.86

$\bigtriangleup t_{f} = 3 \times 1.86 \times 1.12$

$\bigtriangleup t_{f} = 6.2$

the freezing point of water decreases by 6.2 °c

therefore we can say that, the solution will have a higher boiling point and a lower freezing point

Answer from: Quest

Burned piece of steel wool does not gain mass. so only d could be true.

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