Use the values below to answer the question that follows. ΔHsub of MgΔHf of MgCl2(s)1st ionization energy of Mg2nd ionization energy of MgBond energy of Cl2 Electron affinity of Cl=147.7 kJ/mol=−641.3 kJ/mol=737 kJ/mol=1450.7 kJ/mol=242 kJ/mol=−349 kJ/mol For the values given above, "sub" stands for sublimation and "f" stands for formation. What is the lattice energy (lattice enthalpy) of MgCl2? Your answer should have three significant figures.