21. Calculate the molarity of each of the following solutions: A.10.5 g NaCl in 350.0 mL of solution B.40.7 g LiClo, -3H,0 in 125 mL of solution

2b2t

explanation:

2b2t

16

explanation:

the marks go by 4s

answer: i dont know the answer but this might

explanation:

l

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o