Read the excerpt from Julius Caesar, act 2, scene 4. PORTIA. I prithee, boy, run to the Senate House;

Stay not to answer me, but get thee gone.—

Why dost thou stay?

LUCIUS. To know my errand, madam.

PORTIA. I would have had thee there and here again5

Ere I can tell thee what thou shouldst do there.

[Aside] O constancy, be strong upon my side;

Set a huge mountain 'tween my heart and tongue.

I have a man’s mind, but a woman’s might.

How hard it is for women to keep counsel!10

[To LUCIUS] Art thou here yet?

LUCIUS. Madam, what should I do?

Run to the Capitol, and nothing else?

And so return to you, and nothing else?

PORTIA. Yes, bring me word, boy, if thy lord look well,

For he went sickly forth; and take good note15

What Caesar doth, what suitors press to him.

Hark, boy, what noise is that?

LUCIUS. I hear none, madam.

Whic

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be