An object was measured by a worker as 17.400 cm long, however, the manufacturer
specifications list the length of the object
at 17.900 cm. What is the percent error in
the worker's measurement?
a. 2.79% or b. 2.87%

2.79 % error

Explanation:

Percent Error = 100 x [(Actual - Measured) / Actual]

Percent Error = 100 x [(17.900 - 14.700) / 17.900]

Percent Error = 100 x [0.5 / 17.900]

Percent Error = 100 x 0.02793

Percent Error = 2.7932 % or 2.79 %

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%