According to Hebrews 11, what did Abraham believe God would do if Isaac was slain as a sacrifice? Please help me I need it for tonight!

ABRAHAM DIDN’T THINK ISAAC WOULD DIE!

When they reached the mountain, Abraham told his servant, “Stay here with the donkey; I and the boy will go over there and worship and come again to you” . The text is careful to include both Abraham and Isaac in the return journey.

Or consider Isaac’s question about where the lamb for the sacrifice would come from. Abraham responds, “God himself will provide the lamb”. It seems Abraham prepared himself to do what God asked, but he expected something else to happen.

The author of the book of Hebrews gives us insight to Abraham’s thoughts. It says, “He considered that God was able even to raise [Isaac] from the dead” Instead of a resurrection, Abraham was spared the sacrifice.

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g