What volume of hydrogen (in L) is produced
from the complete reaction of 56.49 g of
magnesiu...
What volume of hydrogen (in L) is produced
from the complete reaction of 56.49 g of
magnesium metal at STP?
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Mg(s) + 2HCl(aq) + MgCl2(aq) + H2(g)
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Note: Keep extra digits in any intermediate
calculations! Round to the correct number of
significant figures at the very end.
Remember! 1 mole of gas at STP occupies 22.4 L.
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Answers: 1
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