Using the balanced equation, perform the stoichiometry calculations indicated in a. and b. below 2 H3PO4 + 3 Sr -> 3 H2 + Sr3(PO4)2

a. How many grams of strontium phosphate are produced in the reaction of 65.30 g of strontium with excess phosphoric acid?

b. How many grams of hydrogen are produced?

Thanks.

a) 113g Sr3(PO4)2

b) 1.5g H2

Explanation:

The number of moles of Sr used in the equation

= mass/ molar mass

=65.30/87

= 0.751mol

Since the mole ratio of Sr: Sr3(PO4)2 is 3:1

moles of Sr3(PO4)3 = 1/3*0.751

= 0.25mol

grams of Sr3(PO4)3 is = moles * molar mass

= 0.25 * 452

= 113g

b). Since mole ratio of Sr:H2 is 3:3

moles of H2 = 0.751 * 3/3 ---> 0.751 mol

grams of H2 is = moles * molar mass

= 0.751 * 2

= 1.502g

the answer is   c.) 1575 j.

explanation:

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.