How many liters of hydrogen gas can be produced from 108 g of aluminum metal?show steps please balanced equation
2Al+6HCL yield 2AlCl3 + 3H2

134.4 L

Explanation:

1. Find number of moles for Al

Number of moles

= mass ÷ molar mass

= 108 g ÷ 27

= 4 moles

2. Do comparison

From the equation, 2 moles of Al yields 3 moles of H2 gas.

Therefore, 4 moles of Al should yield 6 moles of H2 gas.

Calculation:

4 moles ÷ 2 moles x 3 moles = 6 moles of H2 gas

3. Convert to liters

Liters of H2 gas

= Number of moles x molar volume

= 6 moles x 22.4 L

= 134.4 L

fe 55.85 g/mol and h2o 18.02 g/mol.