What is the number of moles in 3.2x10^24 atoms of nitrogen? A. 1.9 moles
B. 5.3 moles
C.9.5 moles
D. 19.2 moles

Option B

Explanation:

Use Avogadro constant of 6.02 x 10^23

For Option A,

1.9 moles x (6.02 x 10^23) = 1.1438 x 10^24

For Option B,

5.3 moles x (6.02 x 10^23) = 3.1906 x 10^24

For Option C,

9.5 moles x (6.02 x 10^23) = 5.719 x 10^24

For Option D,

19.2 moles x (6.02 x 10^23) = 1.1558 x 10^25

Therefore, the nearest one to 3.2 x 10^24 is Option B

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole