Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the chemical equation CS2(ℓ) + 3 O2(g) −→ CO2(g) + 2 SO2(g). If 1.33 mol of CS2 is combined with 1.83 mol of O2, identify the limiting reactant. 1. CO2 2. O2 3. CS2 4. SO2.How much excess reactant remains? Answer in units of mol. How much CO2 is formed? Answer in units of mol. How much SO2 is formed?Answer in units of mol

Radon-222 or rn-222 has a half-life of 3.82 days. to determine the fraction of an original sample of rn-222 that remains unchanged after 7.646 days, we calculate the amount of rn-222 remaining after 7.646 days and divide it with the original amount. using 1 gram as a basis and using half-life calculation methods, we can determine that  0.249 or 0.25  grams of rn-222 will remain, and thus the fraction remaining is 0.25 or 1/4.

It depends on how many moles there are, if you have about 4 moles you must divide that number by 2.5 and add 14 to it and you will get your answer.