2 When 0.42g of a gaseous hydrocarbon A is slowly passed over a large quantity of heated copper(II) oxide, CuO, A is completely oxidised. The products are collected and it is found that 1.32 g of C*O_{2} and 0.54g of H_{2}*O are formed. Copper is the only other product of the reaction.

(a) (i) Calculate the mass of carbon present in 1.32 g of CO 2 .

For Use

Use this value to calculate the amount, in moles, of carbon atoms present in 0.42g of A.

(ii) Calculate the mass of hydrogen present in 0.54g of H_{2}*O

Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.42 g of A.

(iii) It is thought that A is an alkene rather than an alkane.

Use your answers to (i) and (ii) to deduce whether this is correct.

Explain your answer.

[5]

most historians agree that gabriel mouton, the vicar of st. paul’s church in lyons, france, is the “founding father” of the metric system. he proposed a decimal system of measurement in 1670. mouton based it on the length of one minute of arc of a great circle of the earth (now called a nautical mile, 1852 meters). he also proposed the swing-length of a pendulum with a frequency of one beat per second as the unit of length (about 25 cm). a pendulum beating with this length would have been fairly easy to produce, thus facilitating the widespread distribution of uniform standards. over the years, his work was revised, improved, and extended by a number of french scientists.

the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).

you didnt put any of the following

5.6⋅10−^19  j

do you need the explaination?