How many grams of copper metal are required to react with 4.00 grams of silver nitrate to produce copper (II) nitrate?

0.7479 grams of copper metal is required to react with 4 grams of silver nitrate...~

0.753 grams of copper metal are required to react with 4.00 grams of silver nitrate to produce copper (II) nitrate

Explanation:

mass = moles * Mr

                      Equation of this reaction:

          Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

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Find moles of silver nitrate:

4 = moles * 170

→ moles

Here we "2" molar ratio before silver nitrate and "1" before copper metal, so copper metal has half the moles of silver nitrate. copper metal has   ÷ 2 =   moles

so find the mass of copper metal:

mass =   * 64

mass of copper is 0.753 grams.

Cause its being chemically applied?

Man i dont know this answer