10 points Question #10: What is the molarity of 51.2 grams of H SO, dissolved in
enough water to make 500 mL of solution? *
A. 104 M
O B.1.04 M
O C. 0.104 M
O D. 10,4 M M
Please need done quick

B

Explanation:

Use the molar mass of H2SO4 to get moles of H2SO4; 51.2g/98.079g=0.522

Divide 500 mL by 1000 to get L

Molarity = moles of solute/L of solution; so divide the moles by 0.5L

14 days is the half-life of phosphorus-32

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24