How many particles would be found in 1.224 g sample of K2O?

7.8286×10^21 particles

Explanation:

atomic mass of potassium = 39.1 u

1 u = 1 g/mol

Potassium (K) = 39.1 g/mol × 2 =  78.2 g/mol

Oxygen (O)     =     16 g/mol × 1  =    16  g/mol

K₂O = 94.2 g/mol

1.224 g / 94.2 g/mol = .013 moles

Avogadro's number = 6.022×10²³

particles = moles x Avogadro's number

particles = .013 moles x 6.022×10^23

particles = 7.8286×10^21 particles

socratic