element K has the following electronic configuration 1s2 2s2 2p6 3s2 . how many unpaired electrons can be found in K

The key to deciphering this is to look at the last bit of information of the electron configuration

3

p

2

.

The '3' informs us that the element is in the 3rd Energy Level or row of the periodic table. The 'p' tells us that the element is found in the p-block which are all of the Groups to the right of the transition metals, columns 13-18. The superscript '2' tells us that the element is found in the 2nd column of the p-block Group 14.

I hope this was helpful.

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots