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Chemistry, 25.02.2022 20:40 gretchcampbell

As instructed, to find a second solution y2(x). (1 − x2)y'' 2xy' = 0; y1 = 1.

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As instructed, to find a second solution y2(x). (1 − x2)y'' 2xy' = 0; y1 = 1....
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