Hydrogen gas and solid gold(III) sulfide are reacted. Pure solid gold metal is formed and gaseous hydrogen sulfide is released. Correctly identify the reactants and products:reactants: a. solid gold, gaseous hydrogen sulfideproducts: hydrogen gas, solid gold(III)
b. sulfidereactants: solid gold, solid gold(III) sulfideproducts: hydrogen gas, gaseous
c. hydrogen sulfidereactants: hydrogen gas, solid gold, gaseousproducts: hydrogen sulfide
d. solid gold(III) sulfidereactants: hydrogen gas, solid gold(III)
e. sulfide products: solid gold, gaseous hydrogen sulfide

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

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