Calculate freezing temperature of.5 m sodium chloride solution. assume that the molality of each solution is .5 m

a. -.93 celsius
b. -1.86 celsius
c. -3.72 celsius
d. -.538 celsius

Given,
Molality = .5M

We know, Kf = 1.86

Now,
Δ T = M x Kf
      = 1.86 * 0.5
      = 0.93 °C

Now,
Freezing point = Initial freezing point - Δ T
                     = 0°C - 0.93°C
                     = -0.93°C
So, the answer is A

Coal i believe hope this

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