How many kilojoules are needed to raise the temperature of 325 grams of water from 15.0 degrees c to 77.0 degrees c?

Given:
m = 325 g, the mass of water
ΔT = 77 - 15 = 62 °C, the change in temperature

Note that
c = 4.184 J/(g-°C), the specific heat of water.

Use the formula
Q = m*c*ΔT
where Q is the heat required for the change in temperature.

Q = (325 g)(4.184 J/g-°C)*(62 °C) = 8.43 x 10⁴ J
That is,
Q = 84.3 x 10³ J = 84.3 kJ

  84.3 kJ

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

Wagons/motorized vehicles