When a 10 ml graduated cylinder is filled to the 10 ml mark, the mass of the water was measured to be 10.085 g at 20ºc. if the density of water is taken to be 0.9975 g/ml at 20ºc, what is the percent error for the 10 ml of water.

The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value  * 100
The || is needed to get the absolute value of the difference. Substituting the values,

Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/0.9975 g/mL  * 100
Percent error = 1.1% 

Ithink that’s it’s b