Three solutions are mixed together to form a single solution; in the final solution, there are 0.2 mol pb(ch3coo)2, 0.1 mol na2s, and 0.1 mol cacl2 present. part a what solid(s) will precipitate? express your answer as a chemical formula. if there is more than one answer, separate them by a comma.

We are given the compounds:

0.2 mol pb(ch3coo)2, 0.1 mol na2s, and 0.1 mol cacl2

Pb will react with both S and Cl to form a solid compound, therefore:

Pb+2 + S-2 ---> PbS(s) 
Pb+2 + 2Cl- ---> PbCl2(s) 

Lead(II) sulfide and Lead(II) chloride will precipitate.

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

b.false that your answer