Diethyl ether is produced from ethanol according to the following equation: 2ch3ch2oh(l) → ch3ch2och2ch3(l) + h2o(l) calculate the percent yield if 76.1 g of ethanol reacts to produce 22.1 g of ether.

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

1) molar ratios

2 moles CH3CH2OH : 1 mol CH3CH2OCH2CH3

3) convert 76.1 g of ethanol to number of moles

number of moles = mass in grams / molar mass

molar mass of CH3CH2OH = 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol = 46 g/mol

number of moles = 76.1 g / 46 g/mol = 1.654 mol

4) calculate theoretical yield: 

2 moles CH3CH2OH / 1 mol CH3CH2OCH2CH3 = 1.65 mol CH3CH2OH / x

=> x = 1.654 / 2 = 0.827 mol CH3CH2OCH2CH3

5) calculate the number of moles in 22.1g of ether

number of moles = mass in grams / molar mass

molar mass of ether = 4*12g/mol + 10*1 g/mol + 16g/mol = 74 g/mol

number of moles of ether = 22.1 g / 74 g/mol = 0.299 moles

6) Percent yield = [actual yield /  theoretical yield] * 100 = [0.299 / 0.827] * 100 = 36.15%

36.2%

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.