If a sample containing 2.00 ml of nitroglycerin (density=1.592g/ml) is detonated, how many total moles of gas are produced?

The overall balanced chemical reaction for this is:

Detonation of Nirtoglycerin 
4 C3H5N3O9 --> 12 CO2 + 6 N2 + O2 + 10 H2O 

Therefore:

2.00 mL x 1.592 g/mL = 3.184 g 
3.184 g / 227.1 /mol = 0.0140 mol nitroglycerin 
4 moles --> 12 + 6 + 1 + 10 = 29 moles of gas 
0.0140 mol x (29/4) = 0.1017 moles of gases or (0.102 mol) 

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

50.23 i believe is correct but don't quote me on that.