Nitrogen gas (n2) reacts with excess hydrogen gas (h2) to produce ammonia (nh3). what is the percent yield of ammonia if the actual yield is 1.03 moles and the theoretical yield is 19.7 grams?
a. 17.5%
b. 35.0%
c. 52.3%
d. 89.0%

Answer : The percent yield of ammonia is, 89.0 %

Explanation :  Given,

Actual yield of = 1.03 mole

Theoretical yield of = 19.7 g

Molar mass of = 17 g/mole

First we have to calculate the actual yield of in terms of mass.

Now we have to calculate the percent yield of

Therefore, the percent yield of ammonia is, 89.0 %

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