An uncharged atom of gold has an atomic number of 79 and an atomic mass of 197. this atom has protons, neutrons, and electrons. an uncharged atom of gold has an atomic number of 79 and an atomic mass of 197. this atom has protons, neutrons, and electrons. 276 . . 118 . . 79 118 . . 79 . . 118 118 . . 276 . . 118 79 . . 276 . . 79 79 . . 118 . . 79

79 protons, 79 electrons and 118 neutrons

Explanation:

Hi, the atomic number of an element is equal to the number of protons it has.

For gold (Au):

If the atom is uncharged (and only if it is uncharged), the number of electrons it has is equal to the number of protons.

For gold (Au):

At last, the atomic mass represents the protons plus the neutrons an atom has in its core. So:

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: