Predict what precipitate will form when a solution of barium chloride is mixed with a solution of potassium sulfate.

BaCl2 + K2SO4↔ BaSO4(s) + 2K+ + 2 SO4-

All group I ions are soluble (everything in the first column of the periodic table) and will always solubilize - including potassium. Barium will combine with the sulfate and form a precipitate. 

Forgot the question hahaha

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !