What is the mass of a 1.69-l sample of a liquid that has a density of 0.921g/ml?

The mass is 1610 g.

D=MV, where D is density, M is mass, V is volume

Known/Given
D=0.921 g/mL
V=1.75 L×1000mL1L=1750 mL

Unknown
M

Equation
D=MV

Solution
Rearrange the equation to isolate the mass and solve for mass.

M=D×V=0.921g/mL×1750mL=1611.75 g=1610 g with three significant figures.

The following diagram helps to understand how to manipulate the density equation so solve for any of the variables.

The following Density Triangle will help you determine how to solve for any missing variable. Put your finger over the missing variable to see what you need to do to solve for it. For example, if you need to find volume, put your finger over the V, and you get M÷D.

https://www.teacherspayteachers.com/Product/Science-Journal-Density-Triangle-Foldable-Completed-4360...

what's the question?

explanation:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"