The equation below represents the overall cell reaction for an electrochemical cell that undergoes a spontaneous reaction. fe(s) + pb2+(aq) mc011-1.jpg fe2+(aq) + pb(s) emc011-2.jpgcell = –0.31 v which reaction is the spontaneous reduction reaction? fe(s) mc011-3.jpg fe2+(aq) + 2e– emc011-4.jpg = –0.44 v fe(s) mc011-5.jpg fe2+(aq) + 2e– emc011-6.jpg = +0.44 v pb2+(aq) + 2e– mc011-7.jpg pb(s) emc011-8.jpg = –0.13 v pb2+(aq) + 2e– mc011-9.jpg pb(s) emc011-10.jpg = +0.13 v

Pb2+(aq) + 2e– >Pb(s) = –0.13 V

Explanation:

Given the question asked, we have to examine the reduction potentials of Fe2+ and Pb2+.

Fe2+= -0.44V

Pb2+= -0.13V

Recall that the moire negative the reduction potential of a species, the less likely it is to participate in spontaneous reduction reactions.

From the data before us, Pb2+ will undergo a spontaneous reduction reaction as shown in the answer.

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.