Pure msg, a common flavor enhancer, exhibits a specific rotation of +24. calculate the ee of a solution whose [α] is +11.

The ee is the short term for enantiomeric excess. The formula for this is given as:

ee = [α] mixture / [α] pure enantiomer

Thus substituting the given values:

ee = + 11 / + 24

ee = 0.4583 = 45.83%

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol