Asample is a mixture of kcl and kbr. when 1.169 g of the sample is dissolved in water and reacted with excess silver nitrate, 1.892 g of solid is obtained. what is the composition by mass percent of the mixture?

Let x be the amount in grams of KCl and y be the amount of KBr. The reaction of each with Silver Nitrate is:

KCl + AgNO₃ → AgCl + KNO₃
KBr + AgNO₃ → AgBr + KNO₃

The solid referred to here are AgCl and AgBr. The solution is as follows:

x+y = 1.169 g or y = 1.169 - x --> eqn 1
amount of AgCl = x(1 mol/74.55 g KCl)(1 mol AgCl/1 mol KCl)(143.32 g AgCl/mol) = 1.9225x
amount of AgBr =  y(1 mol/119 g KBr)(1 mol AgBr/1 mol KBr)(187.77 g AgBr/mol) = 1.5779y
Thus,
1.9225x + 1.5779y = 1.892 --> eqn 2

Substituting eqn 1 to eqn 2,
1.9225x + 1.5779(1.169 - x) = 1.892
Solving for x,
x = 0.1377 g KCl
y = 1.169 - 0.1377 = 1.0313 g KBr

Mass Percent of KCl = 0.1377/(0.1377+1.0313) * 100 = 11.78% KCl
Mass Percent of KBr = 1.0313/(0.1377+1.0313) * 100 = 88.22% KBr

Okay well gravitational energy is matter forced by gravity making energy though the kinetic energy then the electric energy produces electricity from the kinetic energy and the kinetic energy gets its energy from the gravitational energy. was that the answer you wanted or something else?