What mass of co2 would be produced by the neutralization of 25.0 ml of 6.00m h2so4 using excess nahco3?

The complete balanced reaction is:

H2SO4  +  2NaHCO3  -->  Na2SO4 +  2H2O  +  2CO2

Then we calculate the number of moles of H2SO4:

moles H2SO4 = 0.025 L * 6 moles / L = 0.15 moles

From stoichiometry of the balanced equation:

moles CO2 = 0.15 moles H2SO4 * (2 moles CO2 / 1 mole H2SO4) = 0.30 moles

The molar mass of CO2 is 44 g / mol, therefore the mass produced is:

mass CO2 = 0.30 moles * (44 g/ mol) = 13.2 g CO2

13.2 g CO2