How many fe(ii) ions are there in 15.0 g of feso4?

Answer : The number of Fe(II) ions present are

Explanation : Given,

Mass of = 15.0 g

Molar mass of   = 152 g/mole

First we have to calculate the moles of

Now we have to calculate the number of Fe(II) ions.

In , there 1 atom of iron ion and 1 atom of sulfate ion.

As we know that,

1 mole of substance always contains number of atoms or ions.

As, 1 mole of contains number of Fe(II) ions.

So, 0.0987 mole of contains number of Fe(II) ions.

Therefore, the number of Fe(II) ions present are

h let me think

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.