How many grams of hydrogen (h) would need to react with 190 grams of fluorine (f) to make 200 grams of hf (hydrofluoric acid)? question 6 options: 200 20 10 5

               10 g of H₂

The Balance chemical equation is as follow,

                                       F₂  +  H₂    →    2 HF

Step 1: Calculate Amount of F₂ required to form 200 g of HF:

According to balance equation,

                  40 g (2 mol) HF is formed by  =  38 g (1 mol) of F₂

So,

                        200 g of HF will be formed by  =  X g of F₂

Solving for X,

                     X  =  (200 g × 38 g) ÷ 40 g

                    X  =  190 g of F₂

Step 2: Calculate amount of H₂ to react with 190 g of F₂:

According to equation,

                         38 g (1 mol) F₂ required  =  2 g (1 mol) of H₂

So,

                                190 g of F₂ will require  =  X g of H₂

Solving for X,

                      X =  (190 g × 2 g) ÷ 38 g

                     X =  10 g of H₂

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.