Determine the charge on each ion in the following compounds, and name the compound. spelling counts!

1. Mg₃N₂: Magnesium nitride

charge Mg = +2

charge N = -3

2. Al₂S₃: Aluminum sulfide

charge Al = +3

charge S = -2

The naming of chemical compounds is giving a special name to a compound that aims to facilitate the classification of compounds and facilitate the identification of a compound. The rules for naming chemical compounds have been determined by the IUPAC (International Union of Pure and Applied Chemistry)

This nomenclature includes the naming of ion compounds, covalent compounds, and polyatomic

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

Metal: cation, positively charged.

Nonmetal: negative anion.

The anion cation's charge is crossed

Example:

Fe₂S₃

Fe charge = +3

S charge = -2

The name: metal + non-metal + -ide

Example: BaCl₂ -> Barium chloride

For transition metals, which have several oxidation charges / numbers, write the oxidation number in roman numbers

Example: SnO: lead (II) oxide

SnO₂: lead (IV) oxide

The naming: name non-metal + non-metal + suffix -ide

In the elements given the prefix mono, di, tri, tetra, penta if more than one element is formed

Example:

SO₂: Sulfur dioxide

SO₃: Sulfur trioxide

The question that needs to be completed is

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts! (a) Mg₃N₂ Name: Charges: Mg N (b) Al₂S₃ Name: Charges: Al S

1. In the compound Mg₃N₂

load Mg = +2

charge N = -3

Name: Magnesium nitride

2. In the Al₂S₃ compound

Al load = +3

load S = -2

Name: Aluminum sulfide

the chemical formula for each ionic compound.

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two functional groups that contain ionic charges

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Binary ionic compounds

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Keywords: ionic compound, the naming of chemical compounds

the maximum mass of nh3 is nh3 in grams

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2