How many grams of o are in 585 g of li2o

313.3 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

1 mole of contains = 1 mole of Oxygen atom (O)

Thus 19.58 moles of contain = of Oxygen atom (O)

Mass of Oxygen (O)=

Thus there are 313.3 grams of O are in 585 g of .

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.