Asample of calcium carbonate, caco3(s) absorbs 45.5 j of heat, upon which the temperature of the sample increases from 21.1 °c to 28.5 °c. if the specific heat of calcium carbonate is 0.82 j/g·˚c, what is the mass (in grams) of the sample?

The mass of the sample of Calcium carbonate is 0.195g

The heat capacity formula,

\

Where,

Q- Heat absorbed = 45.5 J

C- specific heat capacity of  

- change in temperature = 280.5 k

m - mass = ?

Solving Equation for m

Hence , we can conclude that the mass of sample is 0.195g.

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