Matt did an experiment to study the solubility of two substances. he poured 100 ml of water at 20 °c into each of two beakers labeled a and b. he put 50 g of substance a in the beaker labeled a and 50 g of substance b in the beaker labeled b. the solution in both beakers was stirred for 1 minute. the amount of substance left undissolved in the beakers was weighed. the experiment was repeated for different temperatures of water and the observations were recorded as shown. experimental observationssubstance mass of undissolved substance at different temperatures (gram) 20 °c 40 °c 60 °c 80 °c a 50 50 50 50 b 10 8 5 2 part 1: which, if any, substance is soluble in water? part 2: explain how the data you determine solubility for both substances for temperatures 20 °c to 80 °c.

Part 1 : Answer is only B substance is soluble in water.

In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.

Part 2 : Substance A is not soluble in water and substance B is soluble in water.

According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.

But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.

c, liquids evaporate, creating a gas