Nitroglycerin (c3h5n3o9) is a powerful explosive. its decomposition may be represented by 4c3h5n3o9 → 6n2 12co2 10h2o o2 this reaction generates a large amount of heat and gaseous products. it is the sudden formation of these gases, together with their rapid expansion, that produces the explosion. (a) what is the maximum amount of o2 in grams that can be obtained from 4.50 × 102 g of nitroglycerin

The maximum mass of O₂ that can be obtained from 4.5×10² g of nitroglycerin is 15.86 g

The balanced equation for the reaction is given below:

Next, we shall determine the mass of C₃H₅N₃O₉ that decomposed and the mass of O₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₃H₅N₃O₉ = (12×3) + (5×1) + (14×3) + (16×9)

= 36 + 5 + 42 + 144

= 227 g/mol

Molar mass of O₂ = 2 × 16 = 32 g/mol

From the balanced equation above,

908 g of C₃H₅N₃O₉ decomposed to produce 32 g of O₂.

Finally, we shall determine the mass of O₂ that will be produce from the decomposition of 4.5×10² g of C₃H₅N₃O₉. This can be obtained as follow:

From the balanced equation above,

908 g of C₃H₅N₃O₉ decomposed to produce 32 g of O₂.

Therefore, 4.5×10² g of C₃H₅N₃O₉ will decompose to produce = = 15.86 g of O₂

Thus, the maximum mass of O₂ obtained from 4.5×10² g of nitroglycerin is 15.86 g

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