How would you prepare 1.00 l of a 0.400m solution of copper(ii)sulfate, cuso4?

To prepare the solution of given molarity, we add 63.8 g of copper (II) sulfate to the solution.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of copper(II)sulfate solution = 0.400 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

To calculate the mass of copper(II)sulfate for given number of moles, we use the equation:

Molar mass of copper(II)sulfate = 159.61 g/mol

Moles of copper(II)sulfate = 0.400 moles

Putting values in above equation, we get:

Hence, to prepare the solution of given molarity, we add 63.8 g of copper (II) sulfate to the solution.

where's the diagram?