For co2 the van der waals constants are a=3.59 atm • l2/mol2 and b=0.0427 l/mol. calculate the pressure exerted by 2.50 moles of co2 confined in a volume of 5.00 l at 450 k.

The pressure is 17.97 atm; [P + a](V-nb) = nRT; [P + 3.59 atm·L²mol⁻²](5.00 L - 2.50 mol × 0.0427 mol·L⁻¹) = 2.50 mol × 0.08206 L·atm·K⁻¹mol⁻¹ × 450 K; (P + 0.898 atm)(5.00 L - 0.107 L) = 92.3 L·atm; (P + 0.898 atm)(4.89) = 92.3 atm; P + 0.898 atm = = 18.87 atm; P = 18.87 atm - 0.898 atm = 17.97 atm

The answer is d.potassium