How many calcium ions are in 0.3 mol of cacl2?

One mole of CaCl2 contains 1 mole of calcium.
Therefore, 0.3 moles of CaCl2 will contain 0.3 moles of calcium.

1 mole of calcium contains Avogadro's number of ions, therefore, 0.3 moles will contain:
number of ions = 0.3 * 6.02 * 10^23 = 1.806 * 10^23 ions

1.8 x 10^23 calcium ions Each mole of CaCl2 will produce 1 mole of calcium ions. So just multiply the number of moles of CaCl2 by avogadro's number. Therefore 0.3 * 6.0221409 x 10^23 = 1.806642 x 10^23 So there will be 1.8 x 10^23 calcium ions in 0.3 moles of CaCl2.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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