How many grams are there in 7.50 x 10^23 molecules of h2so4

123 g

Explanation:

1 mole of H₂SO₄ contains 6.02 × 10²³ molecules of H₂SO₄ (Avogadro's number). The moles of H₂SO₄ represented by 7.50 × 10²³ molecules of H₂SO₄ are:

7.50 × 10²³ molecules × (1 mol/ 6.02 × 10²³ molecules) = 1.25 mol

The molar mass of H₂SO₄ is 98.08 g/mol. The mass of H₂SO₄ represented by 1.25 mol is:

1.25 mol × (98.08 g/mol) = 123 g

a corroding iron, if that's one of your choices

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2