How many grams of acetic anhydride are needed to react with 4.65 g of salicylic acid?

From the equation, one mole of acetic anhydride is needed to react with one mole of salicylic acid. From the stoichiometry of the equation, we get 4.65 g x 102.10 g acetic anhydride/1 mol divided by 138.13 g salicylic acid per mole. This gives us 3.44 g of salicylic acid.

The answer is b carbon-14. the radioactive isotope of carbon used in carbon dating has a half-life of 5730 years. potassium-40 is used to date 1.25 billion years

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.