Suppose 4 moles of a react with excess amount of b to produce 382.5 g of c, calculate the percent yield of c. (the molar mass of c is 310.2 g/mol)

To find the percent yield, we first need to write this out as an equation: 3A + 2B --> C + 6D. The moles of C equals 1/3 times the moles of A. Therefore, the moles of C equals 4/3. The theoretical yield equals = moles x molar mass of C. (4/3) x (310.2) = 413.6g The percent yield equals actual yield/theoretical yield x 100%. 382.5g/413.6g x 100% = 92.48%

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