Calculate the percentage composition of barium nitrate (ba(no3)2). choose the correct percentages for ba, n, and o.

The molar masses of each element are:

Ba =137.3 g/mol 
N = 14 g/mol 
O = 16 g/mol

Calculating the total mass by multiplying with number of moles:

Ba = 137.3 g/mol * 1 mol = 137.3 g

N = 14 g/mol * 2 mol = 28 g

O = 16 g/mol * 6 mol = 96 g

Total 261.3g 

Ba: 137.3/261.3 = 52.55% 
N: 96/261.3 = 36.73% 
O: 24/261.3 = 10.72% 

52.55% Ba, 10.72% N, 36.73% O

you gotta add the following molecules so we can give u an answer

explanation: