Acompound composed of only carbon and chlorine is 85.5% chlorine by mass. propose a lewis structure for the lightest of the possible compounds that allows each atom to have a complete octet without formal charges. draw the molecule by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons.

Answer is in picture below.

Use 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; mass percentage of the chlorine in the compound.

m(Cl) = 0.855 · 100 g.

m(Cl) = 85.5 g; mass of chlorine.

m(C) = 100 g - 85.5 g.

m(C) = 14.5 g; mass of carbon.

n(Cl) = m(Cl) ÷ M(Cl).

n(Cl) = 85.5 g ÷ 35.45 g/mol.

n(Cl) = 2.41 mol; amount of chlorine.

n(C) = 14.5 g ÷ 12 g/mol.

n(C) = 1.21 mol; amount of carbon.

n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.

This compound is dichlorocarbene CCl₂.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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