What is the mass of silver metal produced from 6.35 g of copper when copper reacts with excess silver nitrate in a single replacement reaction? g?

21.6 grams The balanced equation for the reaction is Cu + 2AgNO3 ==> 2Ag + Cu(NO3)2 So you can easily determine that for each mole of copper used, 2 moles of silver are produced. So let's lookup the atomic weights of copper and silver. Atomic weight copper = 63.546 Atomic weight silver = 107.8682 Moles copper = 6.35 g / 63.546 g/mol = 0.099927611 mol Since we'll produce 2 moles of silver per mole of copper used, we get 0.099927611 mol * 2 = 0.199855223 mol And to get the mass, just multiply by the atomic weight of silver. So 0.199855223 * 107.8682 = 21.55802316 g Finally, round to 3 significant figures, giving 21.6 g.

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes