When 50.0 ml of a 0.3000 m agno3 solution is added to 50.0 ml of a solution of mgcl2, an agcl precipitate forms immediately. the precipitate is then filtered from the solution, dried, and weighed. if the recovered agcl is found to have a mass of 0.1183 g, what as the concentration of magnesium ions in the original mgcl2 solution?

Explanation:

The balanced reaction is:

We know, number of moles =

Therefore, moles of AgCl formed=        ( Molar mass of AgCl is 143 gm)

From the balanced equation 1 mol of forms 2 mol of AgCl.

Therefore, 0.000827 mol of AgCl was formed by

Now concentration of

Hence, this is the required solution.

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